Making Change Solution

#include <stdio.h>

#include<conio.h>

int change(float total, int *hundred, int *fifty, int *twenty, int *ten, int *five, int *one);

void print(float total, int hundred, int fifty, int twenty, int ten, int five, int one);

int main(void)

{

             int hundred,fifty, twenty, ten, five, one,sum=0;

             float total;

             clrscr();

             printf("\nPlease enter an amount of money: \n");

             scanf("%f", &total);

             change(total,&hundred, &fifty, &twenty, &ten, &five, &one);

             print(total, hundred, fifty, twenty, ten, five, one);

             sum=hundred+fifty+twenty+ten+five+one;

             printf("No of cions are:%d ",sum);

             getch();

}

int change(float total, int *hundred, int *fifty, int *twenty, int *ten, int *five, int *one)

{

            if( total >= 100.00)

                        *hundred =(total /100.00);

            if( total >= 50.00 )

                        *fifty = (total- (*hundred * 100.00))/50.00;

             if( total >= 20.00 )

                        *twenty = (total - (*hundred * 100.00)- (*fifty * 50.00)) / 20.00;

             if( total >= 10.00 )

*ten = (total - (*hundred * 100.00) - (*fifty * 50.00) - (*twenty *     20.00)) / 10.00;

             if( total >= 5.00 )

*five = (total - (*hundred * 100.00) - (*fifty * 50.00) - (*twenty * 20.00) - (*ten * 10.00)) / 5.00;

            if( total >= 1.00 )

*one = (total - (*hundred * 100.00) - (*fifty * 50.00) - (*twenty * 20.00) - (*ten * 10.00)-(*five * 5)) / 1.00;

                        return 0;

}

void print(float total, int hundred, int fifty, int twenty, int ten, int five ,int one)

{

            printf("\nTOTAL VALUE ENTERED: Rs %.2f", total);

            printf("\n%3d No of 100 Rs coin \n", hundred);

            printf("\n%3d  No of 50 Rs coin \n", fifty);

            printf("\n%3d No of 20 Rs coin \n", twenty);

            printf("\n%3d No of 10 Rs coin \n", ten);

            printf("\n%3d No of 5 Rs coin \n", five);

           printf("\n%3d No of 1 Rs coin \n", one);

}